osmo-bsc/tests/handover/test_dyn_ts_balance_congest...

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# To balance congestion, consider cross effects between TCH/F and TCH/H when occupying a dynamic timeslot in the target:
# when balancing of TCH/F congestion would take up a dyn TS in the target, reducing TCH/H availability, the handover
# should not cause worse TCH/H congestion than in the source cell.
create-bts trx-count 1 timeslots c+s4 TCH/F TCH/F TCH/F TCH/F TCH/F TCH/F PDCH
create-bts trx-count 1 timeslots c+s4 TCH/F TCH/F TCH/F TCH/F dyn dyn PDCH
# for this test, avoid changing a TCH/F to a TCH/H by using a non-AMR codec
codec tch/f FR
network
bts 0
handover2 min-free-slots tch/f 2
bts 1
handover2 min-free-slots tch/f 4
handover2 min-free-slots tch/h 4
set-ts-use trx 0 0 states * TCH/F TCH/F TCH/F TCH/F TCH/F TCH/F *
set-ts-use trx 1 0 states * TCH/F TCH/F TCH/F TCH/F pdch pdch *
meas-rep lchan * * * * rxlev 40 rxqual 0 ta 0 neighbors 30
expect-no-chan
# bts 0 is full for TCH/F. Looking at TCH/F, by target_overbooked_after_ho==75% < current_overbooked_before_ho==100%, a
# congestion balancing to bts 1 would be performed. But the TCH/F on the target cell would occupy a dynamic timeslot.
# That would reduce the TCH/H free slots by two and cause TCH/H being overbooked by 50%. On the source cell, TCH/H is
# not congested. No handover is performed because 50% in the target is more congestion for TCH/H than 0% in the source
# cell.
congestion-check
expect-no-chan
# If there is no constraint on TCH/H in the target cell, the handover does take place.
network
bts 1
handover2 min-free-slots tch/h 2
congestion-check
expect-ho from lchan 0 0 1 0 to lchan 1 0 5 0