35 lines
1.4 KiB
Plaintext
35 lines
1.4 KiB
Plaintext
# If a handover from one TCH kind to the other occupies a dynamic timeslot,
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# also adhere to congestion constraints of the other TCH kind, since taking up
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# a dyn TS may reduce the available slot count for both kinds of TCH.
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create-bts trx-count 1 timeslots c+s4 TCH/F TCH/F TCH/F dyn dyn dyn PDCH
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create-bts trx-count 1 timeslots c+s4 TCH/F TCH/F TCH/F dyn dyn dyn PDCH
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# A TCH/H has better rxlev at a neighbor, and the neighbor's TCH/H slots would
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# not become congested. But taking up a neighbor's dynamic timeslot for TCH/H
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# would reduce the TCH/F availability to cause congestion on TCH/F. No HO.
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network
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handover2 min-free-slots tch/f 2
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handover2 min-free-slots tch/h 2
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set-ts-use trx 0 0 states * - - - TCH/H- pdch pdch *
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set-ts-use trx 1 0 states * TCH/F TCH/F TCH/F TCH/HH pdch pdch *
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meas-rep lchan * * * * rxlev 40 rxqual 0 ta 0 neighbors 30
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expect-no-chan
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meas-rep lchan 0 0 4 0 rxlev 20 rxqual 0 ta 0 neighbors 40
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# no handover because that results in congestion on TCH/F in bts 1
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expect-no-chan
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# Now the same situation, except there already is a half occupied TCH/H, hence an added TCH/H would not change the TCH/F
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# situation. The handover is performed.
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set-ts-use trx 0 0 states * - - - TCH/H- pdch pdch *
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set-ts-use trx 1 0 states * TCH/F TCH/F TCH/F TCH/HH TCH/H- pdch *
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meas-rep lchan 0 0 4 0 rxlev 20 rxqual 0 ta 0 neighbors 40
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expect-ho from lchan 0 0 4 0 to lchan 1 0 5 1
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