lib_generic memset: fill one word at a time if possible
If the destination is aligned, fill ulong values until possible. Then fill remaining part by byte. Signed-off-by: Alessandro Rubini <rubini@unipv.it> Acked-by: Andrea Gallo <andrea.gallo@stericsson.com> Acked-by: Mike Frysinger <vapier@gentoo.org>
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@ -403,10 +403,26 @@ char *strswab(const char *s)
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*/
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*/
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void * memset(void * s,int c,size_t count)
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void * memset(void * s,int c,size_t count)
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{
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{
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char *xs = (char *) s;
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unsigned long *sl = (unsigned long *) s;
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unsigned long cl = 0;
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char *s8;
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int i;
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/* do it one word at a time (32 bits or 64 bits) while possible */
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if ( ((ulong)s & (sizeof(*sl) - 1)) == 0) {
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for (i = 0; i < sizeof(*sl); i++) {
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cl <<= 8;
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cl |= c & 0xff;
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}
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while (count >= sizeof(*sl)) {
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*sl++ = cl;
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count -= sizeof(*sl);
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}
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}
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/* fill 8 bits at a time */
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s8 = (char *)sl;
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while (count--)
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while (count--)
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*xs++ = c;
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*s8++ = c;
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return s;
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return s;
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}
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}
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