properly ignoring signals rised by a thread which is in listening state

This commit is contained in:
Martin Willi 2007-05-08 12:58:33 +00:00
parent 6874bf698c
commit d08b27799a
1 changed files with 8 additions and 11 deletions

View File

@ -299,7 +299,6 @@ static void vsignal(private_bus_t *this, signal_t signal, level_t level,
while (iterator->iterate(iterator, (void**)&listener))
{
va_list args_copy;
va_copy(args_copy, args);
if (!listener->signal(listener, signal, level, thread,
ike_sa, format, args_copy))
@ -315,15 +314,11 @@ static void vsignal(private_bus_t *this, signal_t signal, level_t level,
iterator = this->active_listeners->create_iterator(this->active_listeners, TRUE);
while (iterator->iterate(iterator, (void**)&active_listener))
{
/* if the thread raising the signal is the same as the one that
* listens, we skip it. Otherwise we have a deadlock */
if (active_listener->id == pthread_self())
{
continue;
}
/* wait until it is back */
while (active_listener->state == REGISTERED)
/* wait until all threads are registered. But if the thread raising
* the signal is the same as the one that listens, we skip it.
* Otherwise we would deadlock. */
while (active_listener->id != pthread_self() &&
active_listener->state == REGISTERED)
{
pthread_cond_wait(&active_listener->cond, &this->mutex);
}
@ -346,7 +341,9 @@ static void vsignal(private_bus_t *this, signal_t signal, level_t level,
iterator->reset(iterator);
while (iterator->iterate(iterator, (void**)&active_listener))
{
while (active_listener->state == REGISTERED)
/* do not wait for ourself, it won't happen (see above) */
while (active_listener->id != pthread_self() &&
active_listener->state == REGISTERED)
{
pthread_cond_wait(&active_listener->cond, &this->mutex);
}