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HWPOISON: Allow schedule_on_each_cpu() from keventd

Right now when calling schedule_on_each_cpu() from keventd there
is a deadlock because it tries to schedule a work item on the current CPU
too. This happens via lru_add_drain_all() in hwpoison.

Just call the function for the current CPU in this case. This is actually
faster too.

Debugging with Fengguang Wu & Max Asbock

Signed-off-by: Andi Kleen <ak@linux.intel.com>
This commit is contained in:
Andi Kleen 2009-10-14 06:22:47 +02:00
parent 5d5429af06
commit 65a6446434
1 changed files with 19 additions and 2 deletions

View File

@ -667,21 +667,38 @@ EXPORT_SYMBOL(schedule_delayed_work_on);
int schedule_on_each_cpu(work_func_t func)
{
int cpu;
int orig = -1;
struct work_struct *works;
works = alloc_percpu(struct work_struct);
if (!works)
return -ENOMEM;
/*
* when running in keventd don't schedule a work item on itself.
* Can just call directly because the work queue is already bound.
* This also is faster.
* Make this a generic parameter for other workqueues?
*/
if (current_is_keventd()) {
orig = raw_smp_processor_id();
INIT_WORK(per_cpu_ptr(works, orig), func);
func(per_cpu_ptr(works, orig));
}
get_online_cpus();
for_each_online_cpu(cpu) {
struct work_struct *work = per_cpu_ptr(works, cpu);
if (cpu == orig)
continue;
INIT_WORK(work, func);
schedule_work_on(cpu, work);
}
for_each_online_cpu(cpu)
flush_work(per_cpu_ptr(works, cpu));
for_each_online_cpu(cpu) {
if (cpu != orig)
flush_work(per_cpu_ptr(works, cpu));
}
put_online_cpus();
free_percpu(works);
return 0;