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ipv6: correct return on ipv6_rcv() packet drop 

The routine ipv6_rcv() uses magic number 0 for a return when it drops a
packet. This corresponds to NET_RX_SUCCESS, which is obviously
incorrect. Correct this by using NET_RX_DROP instead.

ps. It isn't exactly clear who the IPv6 maintainers are, apologies if
I've missed any.

Signed-off-by: Mark Smith <markzzzsmith@yahoo.com.au>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Mark Smith 2009-07-06 11:26:24 +00:00 committed by David S. Miller
parent b7cb8c2c82
commit 5c91face51
1 changed files with 3 additions and 3 deletions
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6
net/ipv6/ip6_input.c
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@ -63,7 +63,7 @@ int ipv6_rcv(struct sk_buff *skb, struct net_device *dev, struct packet_type *pt
if (skb->pkt_type == PACKET_OTHERHOST) {
kfree_skb(skb);
return 0;
return NET_RX_DROP;
}
rcu_read_lock();
@ -133,7 +133,7 @@ int ipv6_rcv(struct sk_buff *skb, struct net_device *dev, struct packet_type *pt
if (ipv6_parse_hopopts(skb) < 0) {
IP6_INC_STATS_BH(net, idev, IPSTATS_MIB_INHDRERRORS);
rcu_read_unlock();
return 0;
return NET_RX_DROP;
}
}
@ -149,7 +149,7 @@ err:
drop:
rcu_read_unlock();
kfree_skb(skb);
return 0;
return NET_RX_DROP;
}
/*